(x^2)-0.65x=40

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Solution for (x^2)-0.65x=40 equation:



(x^2)-0.65x=40
We move all terms to the left:
(x^2)-0.65x-(40)=0
a = 1; b = -0.65; c = -40;
Δ = b2-4ac
Δ = -0.652-4·1·(-40)
Δ = 160.4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.65)-\sqrt{160.4225}}{2*1}=\frac{0.65-\sqrt{160.4225}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.65)+\sqrt{160.4225}}{2*1}=\frac{0.65+\sqrt{160.4225}}{2} $

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